Extracting individual characters

Posted by Slayer on Wed 16 May 2007 02:05 AM — 12 posts, 46,197 views.

Slayer Wed 16 May 2007 02:05 AM #0

Taken from a previous thread, lost my username... oh well.

I want to extract individual characters from a line that have different ansi to the rest of the line.
The script below separates and displays the whole line;

function my_trigger (name, line, wildcards, styles)

for k, v in ipairs (styles) do
print ("TEST: ", v.text)
end -- for loop

end -- my_trigger

ie, atm if I triggered of a line, where (x) indicates x is a different colour, such as: This i(s) a tes(t) li(n)e.

It would give me
TEST: This i
TEST: s
TEST: a tes
TEST: t
TEST: li
TEST: n
TEST: e.

Anyway to make it ignore certain colours, or ignore anything that has more than 1 character?
Oh and also to have it print the extracted chars on the same line? So the above example would give me:
TEST: stn
Cheers,
DS

Shaun Biggs USA Wed 16 May 2007 02:20 AM #1


ignore = { ["red"] = false, ["blue"] = false }
function my_trigger (name, line, wildcards, styles)
  local temp = "TEST: "
  for k, v in ipairs (styles) do
    if string.len(v.text) == 1 and ( ignore[ RGBColourToName( v.textcolour ) ] or true ) then
      temp = temp..v.text
    end
  end -- for loop
  print( temp )
end -- my_trigger

David Haley USA Wed 16 May 2007 02:43 AM #2

ignore[ RGBColourToName( v.textcolour ) ] or true

that disjunction will always be true. You probably want to do

not ignore[ RGBColourToName( v.textcolour ) ]

and then set ignore[color] = true when color is something you want to ignore.

Slayer Wed 16 May 2007 02:59 AM #3

Works perfectly. Thanks guys.

Shaun Biggs USA Wed 16 May 2007 03:05 AM #4

Yeah, wasn't thinking about the false or true being true. And I keep forgetting that not nil is true. In my brain I was thinking of having ignore[ RGBColourToName( v.textcolour ) ] ~= false, but used the or out of habit.

Slayer Wed 16 May 2007 03:34 AM #5

Well I cant get the ignore colour to work, but turns out I don't really need it. There is never more than 1 differently coloured character in a row.

Slayer Wed 16 May 2007 06:16 AM #6

Heh colours werent working because I didn't know the 'real' names of the colours... olive/maroon/navy... looks like brown/red/blue to me :P

Ayon Thu 17 May 2007 10:19 PM #7

Hey All

I just switched back to lua, and I am working on a thinger that needs to recognize the color of a single character in a string, but I also need to know the index, that is, where is it located in the string.

say for instance, I will have a string like this:
123456789...etc
'..*. * . < % * .. . .'
Now, let's say, that last asterisk is red, all the rest are grey or white. Now, I need to know which asterisk is red, and what the number position is. This is so I can figure out my place on a map, each character means a certain thing, but only one character means me, who I am.
Code:


function maptracker (sName,sLine,wildcards,styles) 
    line = styles[2] -- The matched text will be here.
    if (string.find(line.text,'*')) then
      --start pseudo code
       i = 1
      for each char in line.text do
        if char == red asterisk then
          my_map_column_position = i
        else
          i = i + 1
        end
      end 
     --end pseudo code
    end
 end
end -- maptracker

So, my main question, is how do I look at each char in the string, and the color of that char, and keep the place number?

Thanks for any help you can give me on this :)

/Ayon

Nick Gammon Australia Forum Administrator Fri 18 May 2007 12:54 AM #8

See this post:

http://mushclient.com/forum/?id=7818

That shows how you can find the colour of a character at a particular column.

Given that, you could do something like this:


for i = 1, #sLine do  -- look at each character
  if string.sub (sLine, i, i) == "*" then  -- if asterisk
    t = GetStyle (styles, i) -- get style table
    if RGBColourToName (t.textcolour) == "red" then
       -- blah blah - do something
    end -- if red
  end -- if asterisk
end -- for loop

Ayon Fri 18 May 2007 01:07 AM #9

Thats absolute genius...it works perfectly.

0.0

Thank you very much on that...

/Ayon

Shaun Biggs USA Tue 22 May 2007 12:03 AM #10

As kind of a side question, is there any way to quickly get the style of a wildcard, or should I just rematch the pattern to get the starting and ending positions in the trigger string and copy it over from the style table?

Nick Gammon Australia Forum Administrator Tue 22 May 2007 02:20 AM #11

If the pattern was simple, you might just use string.find to find the offsets.

Otherwise, rematch using re:exec from the Lua rex library, which returns the offsets of each wildcard, and then you can use those to find the styles.

http://www.gammon.com.au/scripts/doc.php?lua=re:exec