Question about Time_Info

Posted by Kelsid on Tue 13 Nov 2001 08:50 PM — 5 posts, 19,799 views.

Kelsid USA Tue 13 Nov 2001 08:50 PM #0

I had a quick question about time_info.hour:

Basically what Im trying to do, is stop the compression of time in the normal smaug code. Ive figured out where the time_info data is processed in db.c

the code is as follows:


    /*
     * Set time and weather.
     */
    {
	long lhour, lday, lmonth;

	log_string("Setting time and weather");

	lhour		= (current_time - 650336715)
			/ (PULSE_TICK / PULSE_PER_SECOND);
	time_info.hour	= lhour  % 24;
	lday		= lhour  / 24;
	time_info.day	= lday   % 35;
	lmonth		= lday   / 35;
	time_info.month	= lmonth % 12;
	time_info.year	= lmonth / 12;

Basically I want to make time flow with the current_time. I know the problems is either with the 1hour or time_info.hour variables.

Any suggestions would be welcome.

Thanks,
-Kelsid

Nick Gammon Australia Forum Administrator Tue 13 Nov 2001 09:23 PM #1

Probably the simplest thing is to adjust lhour before the calculations. I'm not sure what the compression is, but if it is 5 times, then dividing lhour by 5 should slow it down.

eg.



lhour /= 5;

Alternatively, get the current time and just stuff the hour, day and month into the appropriate variables (time_info.hour and so on).

Kelsid USA Tue 13 Nov 2001 09:45 PM #2

Thanks again Nick,

Actually.... Id rather go with the current_time, How would I get the hours, day, and month from current_time(to make them the time_info equivalants)?

Thanks again,

Kelsid

Nick Gammon Australia Forum Administrator Tue 13 Nov 2001 11:20 PM #3

I haven't tested it, but something like this:



 struct tm *now_time;



 now_time = localtime(&current_time);

 time_info.min = now_time->tm_min;

 time_info.hour = now_time->tm_hour;



// and so on

Kelsid USA Mon 26 Nov 2001 02:25 AM #4

Thanks for a point in the right direction Nick,

For Anyones info....

The problem I encountered was in update.c....

Had a bunch of small modifications there.

-Kelsid